t=-0,5t^2+2,5t

Solution for t=-0,5t^2+2,5t equation:

t=-0.5t^2+2.5t

We move all terms to the left:

t-(-0.5t^2+2.5t)=0

We get rid of parentheses

0.5t^2-2.5t+t=0

We add all the numbers together, and all the variables

0.5t^2-1.5t=0

a = 0.5; b = -1.5; c = 0;
Δ = b2-4ac
Δ = -1.52-4·0.5·0
Δ = 2.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.5)-\sqrt{2.25}}{2*0.5}=\frac{1.5-\sqrt{2.25}}{1}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.5)+\sqrt{2.25}}{2*0.5}=\frac{1.5+\sqrt{2.25}}{1}
$